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27y-y^2=180
We move all terms to the left:
27y-y^2-(180)=0
We add all the numbers together, and all the variables
-1y^2+27y-180=0
a = -1; b = 27; c = -180;
Δ = b2-4ac
Δ = 272-4·(-1)·(-180)
Δ = 9
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{9}=3$$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(27)-3}{2*-1}=\frac{-30}{-2} =+15 $$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(27)+3}{2*-1}=\frac{-24}{-2} =+12 $
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